Inspired by this thread: http://www.toyotanation.com/forum/130-7th-generation-1993-1997/803250-install-drls.html , I figured I'd install low-power high-beam DRLs on my wife's 1994 DX this weekend. I have all the components needed to replicate the Superpro 21500 module: a SPDT relay and power-resistor. Have a tonne of these laying around for impedance-matching hi/low-ohm injectors to various standalone EFI systems:
So first, let's set up the design-parameters for the DRL:
- comes on automatically when you turn key to ON
- powers hi-beams at reduced brightness
- deactivates DRL when headlight-switch is turned to ON and the low-beams turn on
- no interference with high-beam stalk switch push/pull full-power
Ok, that can be accomplished very easily with two relays and a power-resistor. Let's model the stock hi-beam circuit:
Seems pretty simple with known parameters:
- 13-volt supply from alternator/battery
- 65-watt rating on bulbs
- 5-amps per bulb from P=VI
- 2.6-ohms per bulb from V=IR
Now the resistors I have are 1-ohm with 20-watt rating. Plugging the resistor in-line with hi-beams changes the circuit parameters.
Anyone care to find the unknowns if we use the 1-ohm resistor?
What is the resultant total-resistance?
New current-draw?
Power-dissipation by the resistor?
New power-consumption by the hi-beam bulbs?
New light-output (lumens) of hi-beams at the new reduced-power?

So first, let's set up the design-parameters for the DRL:
- comes on automatically when you turn key to ON
- powers hi-beams at reduced brightness
- deactivates DRL when headlight-switch is turned to ON and the low-beams turn on
- no interference with high-beam stalk switch push/pull full-power
Ok, that can be accomplished very easily with two relays and a power-resistor. Let's model the stock hi-beam circuit:

Seems pretty simple with known parameters:
- 13-volt supply from alternator/battery
- 65-watt rating on bulbs
- 5-amps per bulb from P=VI
- 2.6-ohms per bulb from V=IR
Now the resistors I have are 1-ohm with 20-watt rating. Plugging the resistor in-line with hi-beams changes the circuit parameters.

Anyone care to find the unknowns if we use the 1-ohm resistor?
What is the resultant total-resistance?
New current-draw?
Power-dissipation by the resistor?
New power-consumption by the hi-beam bulbs?
New light-output (lumens) of hi-beams at the new reduced-power?